tangent f(x)=x^2-7x+7,(0,7)

解答

切线

f (x) = x^{2} - 7 x + 7, (0, 7)

y = - 7 x + 7

求解步骤

计算

f (x) = x^{2} - 7 x + 7

的斜率:

\frac{df ( x )}{d x} = 2 x - 7

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 7

找到斜率 m=

- 7

且穿过

(0, 7)

的直线:

y = - 7 x + 7

y = - 7 x + 7

x \to 1 + lim (4 x - 2 x^{2})

d er i v a t i v e \frac{x}{x + e ^{(x^{2})}}

d er i v a t i v e y = (5 x + 14)^{5}

(2 + y) d x - 3 (3 - x) d y = 0

\int 18 (200 + t)^{2} d t