derivative g(x)=1+6x+3x^2

Lösung

ableitung von

g (x) = 1 + 6 x + 3 x^{2}

6 x + 6

Schritte zur Lösung

\frac{d}{d x} (1 + 6 x + 3 x^{2})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (6 x) + \frac{d}{d x} (3 x^{2})

\frac{d}{d x} (1) = 0

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (3 x^{2}) = 6 x

= 0 + 6 + 6 x

Vereinfache

= 6 x + 6

\frac{\partial}{\partial y} (cos (x) cos (y))

\int \frac{1}{1 + 3 x + 1} d x

\int e^{4 x + 8} d x

d er i v a t i v e f (x) = \frac{2 x + 1}{x - 1}

\frac{d}{d x} (\frac{\frac{d}{d x} ( ln ( x ) )}{x})