limit as h approaches+6 of (4h)/(h-6)

Lösung

h \to + 6 lim (\frac{4 h}{h - 6})

divergiert

Schritte zur Lösung

h \to 6 lim (\frac{4 h}{h - 6})

Wenn

x \to a - lim f (x) \neq = x \to a + lim f (x)

dann gibt es keine Grenze

h \to 6 + lim (\frac{4 h}{h - 6}) = \infty

h \to 6 - lim (\frac{4 h}{h - 6}) = - \infty

= divergiert

f (x) = 9 - x

\int_{0}^{1} 3 e^{x^{2}} d x

t an g e n t f (x) = x^{3} + 2 x^{2} + 4 x, at x = - 1

d er i v a t i v e f (x) = (2 x - 3) (x + 3)^{3}

\int \frac{x ^{- 1} - x ^{- 3} + x ^{- 3}}{x ^{2}} d x