y^'+3(tan(3x))y=-10cos(3x)

Lösung

y^{^{'}} + 3 (tan (3 x)) y = - 10 cos (3 x)

y = - \frac{10 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

Schritte zur Lösung

y^{'} (x) + 3 (tan (3 x)) y = - 10 cos (3 x)

Solve linear ODE:

y = - \frac{10 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

y = - \frac{10 x}{sec ( 3 x )} + \frac{c _{1}}{sec ( 3 x )}

\int_{0}^{2} \int 1

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