y^'=-y-2x

Lösung

y^{^{'}} = - y - 2 x

y = - 2 (x - 1) + \frac{c _{1}}{e ^{x}}

Schritte zur Lösung

y^{'} (x) = - y - 2 x

Solve linear ODE:

y = - 2 (x - 1) + \frac{c _{1}}{e ^{x}}

y = - 2 (x - 1) + \frac{c _{1}}{e ^{x}}

\int x (1 - 3 x^{2})^{4} d x

d er i v a t i v e ln (x) \cdot x

\frac{\partial}{\partial u} (4 sin (u) cos (v))

\frac{d}{d x} (5 x^{4} - \frac{4}{x})

x \to 0 + lim (tan (2 x))