y^{''}+y+x=0,y(0)=0,y^'(1)=0

Lösung

y^{^{''}} + y + x = 0, y (0) = 0, y^{^{'}} (1) = 0

y = - x + \frac{sin ( x )}{cos ( 1 )}

Schritte zur Lösung

y^{''} (x) + y + x = 0

Solve linear ODE:

y = - x + \frac{sin ( x )}{cos ( 1 )}

y = - x + \frac{sin ( x )}{cos ( 1 )}

in v erse l a pl a ce \frac{s + 2}{s ^{2} + 4 s + 6}

\frac{d}{d x} ((\frac{2}{5})^{x})

\int (1 + x) (2 x + x^{2})^{5} d x

d er i v a t i v e f (x) = 3 t^{3} - 18 t^{2} + 2

x \to - \infty lim (- x)