What is the tangent of f(x)=x^2-1/x ,(1,0) ?

The tangent of f(x)=x^2-1/x ,(1,0) is y=3x-3

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tangent of f(x)=x^2-1/x ,(1,0)

tangent of

f (x) = x^{2} - \frac{1}{x}, (1, 0)

y = 3 x - 3

Solution steps

Find the slope of

f (x) = x^{2} - \frac{1}{x} : \frac{df ( x )}{d x} = 2 x + \frac{1}{x ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 3

Find the line with slope m=

3

and passing through

(1, 0) : y = 3 x - 3

y = 3 x - 3

What is the tangent of f(x)=x^2-1/x ,(1,0) ?
The tangent of f(x)=x^2-1/x ,(1,0) is y=3x-3