integral of 2x^2-4

Lösung

\int 2 x^{2} - 4 d x

\frac{2 x ^{3}}{3} - 4 x + C

Schritte zur Lösung

\int 2 x^{2} - 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x^{2} d x - \int 4 d x

\int 2 x^{2} d x = \frac{2 x ^{3}}{3}

\int 4 d x = 4 x

= \frac{2 x ^{3}}{3} - 4 x

Füge eine Konstante zur Lösung hinzu

= \frac{2 x ^{3}}{3} - 4 x + C

\int \frac{4}{x + 4 + x} d x

x \to - 1 lim (4 x^{3} - 2 m)

x \to 0 - lim (\frac{x ^{2}}{2} - \frac{1}{x})

\int \frac{1}{sec ( x ) + 1} d x

t an g e n t y = x, (49, 7)