integral from 9 to 10 of 1/((x-9)^{4/3)}

Lösung

\int_{9}^{10} \frac{1}{( x - 9 ) ^{\frac{4}{3}}} d x

divergiert

Schritte zur Lösung

\int_{9}^{10} \frac{1}{( x - 9 ) ^{\frac{4}{3}}} d x

Wende U-Substitution an

= \int_{0}^{1} \frac{1}{u ^{\frac{4}{3}}} d u

Wende die Potenzregel an

= [- \frac{3}{u ^{\frac{1}{3}}}]_{0}^{1}

Berechne die Grenzen:

divergiert

= divergiert

\int_{0}^{6.25} - x^{2} + 5 x d x

\int 15 x^{\frac{1}{4}} d x

a re a 3 x, \frac{1}{x}, x = 27

\frac{\partial}{\partial y} (y^{2 x})

x \to - 2 lim (4 x^{3} + 4 x - 2)