y^{''}+16y=40sin(4t)

Lösung

y^{^{''}} + 16 y = 40 sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) - 5 t cos (4 t)

Schritte zur Lösung

y^{''} (t) + 16 y = 40 sin (4 t)

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) - 5 t cos (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) - 5 t cos (4 t)

\frac{\partial}{\partial y} (e^{x} + e^{y})

y^{^{''}} - 2 y^{^{'}} - y = 0, y (0) = 0, y^{^{'}} (0) = 22

d er i v a t i v e 1

t an g e n t y = e^{4 x}, at x = \frac{1}{4} ln (5)

\frac{d}{d x} ((4 + 8 x) cosh (2 x))