derivative of axcos(2x+bxsin(2x))

Lösung

\frac{d}{d x} (a x cos (2 x) + b x sin (2 x))

a (cos (2 x) - 2 x sin (2 x)) + b (sin (2 x) + 2 x cos (2 x))

Schritte zur Lösung

\frac{d}{d x} (a x cos (2 x) + b x sin (2 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (a x cos (2 x)) + \frac{d}{d x} (b x sin (2 x))

\frac{d}{d x} (a x cos (2 x)) = a (cos (2 x) - 2 x sin (2 x))

\frac{d}{d x} (b x sin (2 x)) = b (sin (2 x) + 2 x cos (2 x))

= a (cos (2 x) - 2 x sin (2 x)) + b (sin (2 x) + 2 x cos (2 x))

\frac{\partial}{\partial x} (cos (x) \cdot sin (x))

\frac{d}{d x} (1 + e^{x^{2}})

\frac{d}{d x} (ln ∣ ln (x) ∣)

d er i v a t i v e y = x^{(\frac{1}{l n ( x )})}

\int sin^{5} (x) \cdot cos^{5} (x) d x