integral of (9x-6)^2

Lösung

\int (9 x - 6)^{2} d x

27 x^{3} - 54 x^{2} + 36 x + C

Schritte zur Lösung

\int (9 x - 6)^{2} d x

Multipliziere aus

(9 x - 6)^{2} : 81 x^{2} - 108 x + 36

= \int 81 x^{2} - 108 x + 36 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 81 x^{2} d x - \int 108 x d x + \int 36 d x

\int 81 x^{2} d x = 27 x^{3}

\int 108 x d x = 54 x^{2}

\int 36 d x = 36 x

= 27 x^{3} - 54 x^{2} + 36 x

Füge eine Konstante zur Lösung hinzu

= 27 x^{3} - 54 x^{2} + 36 x + C

d er i v a t i v e - x e^{x}

a re a y^{2} = x + 4, y^{2} = 2 - x

\int \frac{9 w ^{8} - 5 w ^{5} + 3 w ^{2} - 16}{8 w ^{4}} d w

\int - 5 x^{- 8} d x

\frac{d}{d x} (- \frac{x ^{3} + 8 x ^{2} + 19 x + 12}{( x + 20 )})