What is the derivative of y=(x^2+1) ?

The derivative of y=(x^2+1) is 2x

What is the first derivative of y=(x^2+1) ?

The first derivative of y=(x^2+1) is 2x

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derivative of

y = (x^{2} + 1)

2 x

Solution steps

\frac{d}{d x} ((x^{2} + 1))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (1)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (1) = 0

= 2 x + 0

Simplify

= 2 x

What is the derivative of y=(x^2+1) ?
The derivative of y=(x^2+1) is 2x
What is the first derivative of y=(x^2+1) ?
The first derivative of y=(x^2+1) is 2x