derivative of 2sqrt(x)+\sqrt[3]{x}

解答

\frac{d}{d x} (2 x + 3 x)

\frac{1}{x} + \frac{1}{3 x ^{\frac{2}{3}}}

求解步骤

\frac{d}{d x} (2 x + 3 x)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x) + \frac{d}{d x} (3 x)

\frac{d}{d x} (2 x) = \frac{1}{x}

\frac{d}{d x} (3 x) = \frac{1}{3 x ^{\frac{2}{3}}}

= \frac{1}{x} + \frac{1}{3 x ^{\frac{2}{3}}}

\int 7 sin (\frac{x}{3}) d x

y^{^{'}} = \frac{x ^{4} y ^{3} + 2 x ^{4}}{y ^{2}}

\int \frac{x}{6} e^{x^{2}} d x

\frac{\partial}{\partial x} (sin (7 y^{2} - 7 x y))

\int e^{2 x} (x + 1) d x