(\partial)/(\partial y)(4x^3y^3+3)

解答

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 3)

12 x^{3} y^{2}

求解步骤

\frac{\partial}{\partial y} (4 x^{3} y^{3} + 3)

将

x

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (4 x^{3} y^{3}) + \frac{\partial}{\partial y} (3)

\frac{\partial}{\partial y} (4 x^{3} y^{3}) = 12 x^{3} y^{2}

\frac{\partial}{\partial y} (3) = 0

= 12 x^{3} y^{2} + 0

化简

= 12 x^{3} y^{2}

\frac{d}{d x} (4 x + 5)

\int sin^{3} (4 x) cos^{- 2} (4 x) d x

\int cot^{7} (\frac{x}{2}) csc^{2} (\frac{x}{2}) d x

s l o p e (- 2, - 9), (0, - 3)

\frac{d}{d x} ((x - 3)^{3})