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受欢迎的微积分 >

integral of x/(sqrt(x-10))

解答

\int \frac{x}{x - 10} d x

解答

2 (\frac{1}{3} (x - 10)^{\frac{3}{2}} + 10 x - 10) + C

求解步骤

\int \frac{x}{x - 10} d x

使用换元积分法

= \int 2 (u^{2} + 10) d u

提出常数:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int u^{2} + 10 d u

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= 2 (\int u^{2} d u + \int 10 d u)

\int u^{2} d u = \frac{u ^{3}}{3}

\int 10 d u = 10 u

= 2 (\frac{u ^{3}}{3} + 10 u)

u = x - 10

代回

= 2 (\frac{( x - 10 ) ^{3}}{3} + 10 x - 10)

化简

2 (\frac{( x - 10 ) ^{3}}{3} + 10 x - 10) : 2 (\frac{1}{3} (x - 10)^{\frac{3}{2}} + 10 x - 10)

= 2 (\frac{1}{3} (x - 10)^{\frac{3}{2}} + 10 x - 10)

解答补常数

= 2 (\frac{1}{3} (x - 10)^{\frac{3}{2}} + 10 x - 10) + C

作图

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