(\partial ^2)/(\partial x^2)(2cos(xy^2))

解答

\frac{\partial ^{2}}{\partial x ^{2}} (2 cos (x y^{2}))

- 2 y^{4} cos (x y^{2})

求解步骤

\frac{\partial ^{2}}{\partial x ^{2}} (2 cos (x y^{2}))

\frac{\partial}{\partial x} (2 cos (x y^{2})) = - 2 y^{2} sin (x y^{2})

= \frac{\partial}{\partial x} (- 2 y^{2} sin (x y^{2}))

\frac{\partial}{\partial x} (- 2 y^{2} sin (x y^{2})) = - 2 y^{4} cos (x y^{2})

= - 2 y^{4} cos (x y^{2})

(\frac{d y}{d x}) = (x + y + 7)^{2}

- \frac{x 1 - y ^{2}}{y 1 - x ^{2}} = \frac{d y}{d x}

n = 0 \sum \infty \frac{n ^{2} + 1}{n !}

\frac{d}{d u} (\frac{u - 1}{u + 1})

\frac{d ^{2} y}{d x ^{2}} - \frac{d y}{d x} - 30 y = 0