What is the tangent of y= 1/(3t),(2, 1/6) ?

The tangent of y= 1/(3t),(2, 1/6) is y=-1/12 t+1/3

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tangent of y= 1/(3t),(2, 1/6)

tangent of

y = \frac{1}{3 t}, (2, \frac{1}{6})

y = - \frac{1}{12} t + \frac{1}{3}

Solution steps

Find the slope of

y = \frac{1}{3 t} : \frac{d y}{d t} = - \frac{1}{3 t ^{2}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{1}{12}

Find the line with slope m=

- \frac{1}{12}

and passing through

(2, \frac{1}{6}) : y = - \frac{1}{12} t + \frac{1}{3}

y = - \frac{1}{12} t + \frac{1}{3}

What is the tangent of y= 1/(3t),(2, 1/6) ?
The tangent of y= 1/(3t),(2, 1/6) is y=-1/12 t+1/3