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Popular Calculus >

integral of x^2n^2xx

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Solution

∫x2n2xxdx

Solution

5n2x5​+C
Solution steps
∫x2n2xxdx
Take the constant out: ∫a⋅f(x)dx=a⋅∫f(x)dx=n2⋅∫x2xxdx
Simplify x2xx:x4
=n2⋅∫x4dx
Apply the Power Rule
=n25x5​
Multiply fractions: a⋅cb​=ca⋅b​=5n2x5​
Add a constant to the solution=5n2x5​+C

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Popular Examples

integral of x(3-x)integral of (5e^x)/(e^{2x)+6e^x+9}integral from 0 to 2 of (4x-x^3)inverse oflaplace ((4s-3))/((s^2+8s+24))area x+2y=7,x+8=y^2

Frequently Asked Questions (FAQ)

  • What is the integral of x^2n^2xx ?

    The integral of x^2n^2xx is (n^2x^5)/5+C
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