What is the solution for (dy}{dx}=\frac{x^8-4y)/x ?

The solution for (dy}{dx}=\frac{x^8-4y)/x is y=(x^8)/(12)+(c_{1})/(x^4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dy}{dx}=\frac{x^8-4y)/x

\frac{d y}{d x} = \frac{x ^{8} - 4 y}{x}

y = \frac{x ^{8}}{12} + \frac{c _{1}}{x ^{4}}

Solution steps

\frac{d y}{d x} = \frac{x ^{8} - 4 y}{x}

Solve linear ODE:

y = \frac{x ^{8}}{12} + \frac{c _{1}}{x ^{4}}

y = \frac{x ^{8}}{12} + \frac{c _{1}}{x ^{4}}

What is the solution for (dy}{dx}=\frac{x^8-4y)/x ?
The solution for (dy}{dx}=\frac{x^8-4y)/x is y=(x^8)/(12)+(c_{1})/(x^4)