What is the derivative of (xy)/(x+y) ?

The derivative of (xy)/(x+y) is (y^2)/((x+y)^2)

What is the first derivative of (xy)/(x+y) ?

The first derivative of (xy)/(x+y) is (y^2)/((x+y)^2)

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derivative of

\frac{x y}{x + y}

\frac{y ^{2}}{( x + y ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{x y}{x + y})

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= y \frac{d}{d x} (\frac{x}{x + y})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= y \frac{\frac{d x}{d x} ( x + y ) - \frac{d}{d x} ( x + y ) x}{( x + y ) ^{2}}

\frac{d x}{d x} = 1

\frac{d}{d x} (x + y) = 1

= y \frac{1 \cdot ( x + y ) - 1 \cdot x}{( x + y ) ^{2}}

Simplify

y \frac{1 \cdot ( x + y ) - 1 \cdot x}{( x + y ) ^{2}} : \frac{y ^{2}}{( x + y ) ^{2}}

= \frac{y ^{2}}{( x + y ) ^{2}}

What is the derivative of (xy)/(x+y) ?
The derivative of (xy)/(x+y) is (y^2)/((x+y)^2)
What is the first derivative of (xy)/(x+y) ?
The first derivative of (xy)/(x+y) is (y^2)/((x+y)^2)