(y^2+4)dx-1/((2x+5)^2)dy=0

Lösung

(y^{2} + 4) d x - \frac{1}{( 2 x + 5 ) ^{2}} d y = 0

y = 2 tan (\frac{8 x ^{3}}{3} + 20 x^{2} + 50 x - c_{1})

Schritte zur Lösung

(y^{2} + 4) d x - \frac{1}{( 2 x + 5 ) ^{2}} d y = 0

Solve separable ODE:

y = 2 tan (\frac{8 x ^{3}}{3} + 20 x^{2} + 50 x - c_{1})

y = 2 tan (\frac{8 x ^{3}}{3} + 20 x^{2} + 50 x - c_{1})

\int_{0}^{1} \frac{x ^{2}}{25 + x ^{2}} d x

\int \frac{3}{t ^{4}} cos (\frac{1}{t ^{3}} - 9) d t

\int_{- 8}^{8} \frac{1}{2} (64 - x^{2}) d x

n = 1 \sum \infty \frac{8}{n ^{4}}

y^{^{'}} sin (x) + y cos (x) = 0