limit as t approaches 5 of 1/(t^2-4t-5)-1/(6(t-5))

Lösung

t \to 5 lim (\frac{1}{t ^{2} - 4 t - 5} - \frac{1}{6 ( t - 5 )})

- \frac{1}{36}

Dezimale

- 0.02777 \dots

Schritte zur Lösung

t \to 5 lim (\frac{1}{t ^{2} - 4 t - 5} - \frac{1}{6 ( t - 5 )})

\frac{1}{t ^{2} - 4 t - 5} - \frac{1}{6 ( t - 5 )} = \frac{1}{t ^{2} - 4 t - 5} (1 - \frac{\frac{1}{6 ( t - 5 )}}{\frac{1}{t ^{2} - 4 t - 5}})

= t \to 5 lim (\frac{1}{t ^{2} - 4 t - 5} (1 - \frac{\frac{1}{6 ( t - 5 )}}{\frac{1}{t ^{2} - 4 t - 5}}))

Vereinfache

\frac{1}{t ^{2} - 4 t - 5} (1 - \frac{\frac{1}{6 ( t - 5 )}}{\frac{1}{t ^{2} - 4 t - 5}}) : - \frac{1}{6 ( t + 1 )}

= t \to 5 lim (- \frac{1}{6 ( t + 1 )})

Setze den Wert

t = 5

ein

= - \frac{1}{6 ( 5 + 1 )}

Vereinfache

= - \frac{1}{36}

n = 0 \sum \infty \frac{x ^{n}}{n + 2}

x \to 0 lim (\frac{8}{1 + sin ( x )})

d er i v a t i v e \frac{lo g _{5} ( x )}{6 + x ^{5}}

\frac{\partial}{\partial x} (y cos (y - 2 x))

\int \frac{- y}{y} d y