limit as h approaches 0 of (e^{ah}-1)/h

Lösung

h \to 0 lim (\frac{e ^{ah} - 1}{h})

a

Schritte zur Lösung

h \to 0 lim (\frac{e ^{ah} - 1}{h})

Wende das L'Hopital Theorem an

= h \to 0 lim (\frac{a e ^{ah}}{1})

Setze den Wert

h = 0

ein

= \frac{a e ^{a \cdot 0}}{1}

Vereinfache

= a

y^{^{'}} = 3 - cos (x)

\frac{d}{d x} (e^{(\frac{1}{x}) (l n (1 - 2 x))})

\int \frac{10}{4 x ^{3} - 4 x ^{2} + 5 x} d x

\frac{d}{d x} (\frac{1}{4} x^{2} - 2 x - y)

\frac{\partial}{\partial y} (ln (x y))