(dy)/(dx)=2x(x-4)

Lösung

\frac{d y}{d x} = 2 x (x - 4)

y = 2 (\frac{x ^{3}}{3} - 2 x^{2}) + c_{1}

Schritte zur Lösung

\frac{d y}{d x} = 2 x (x - 4)

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = 2 x (x - 4)

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 2 x (x - 4) d x

\int 2 x (x - 4) d x = 2 (\frac{x ^{3}}{3} - 2 x^{2}) + c_{1}

y = 2 (\frac{x ^{3}}{3} - 2 x^{2}) + c_{1}

\frac{d y}{d x} - \frac{y}{x} = 2 x e^{x}

n = 1 \sum \infty (\frac{2 x + 1}{x})^{n}

\int_{- 48}^{0} \frac{1}{1 - x} d x

\int \frac{cos ( 2 x )}{sin ^{3} ( 2 x )} d x

\frac{\partial}{\partial v} (u - uv)