derivative f(x)=4x^{4/3}-2/3 x^{3/2}+x^2-4x+1

Lösung

ableitung von

f (x) = 4 x^{\frac{4}{3}} - \frac{2}{3} x^{\frac{3}{2}} + x^{2} - 4 x + 1

2 x + \frac{16 x ^{\frac{1}{3}}}{3} - x^{\frac{1}{2}} - 4

Schritte zur Lösung

\frac{d}{d x} (4 x^{\frac{4}{3}} - \frac{2}{3} x^{\frac{3}{2}} + x^{2} - 4 x + 1)

Vereinfache

4 x^{\frac{4}{3}} - \frac{2}{3} x^{\frac{3}{2}} + x^{2} - 4 x + 1 : 4 x^{\frac{4}{3}} - \frac{2 x ^{\frac{3}{2}}}{3} + x^{2} - 4 x + 1

= \frac{d}{d x} (4 x^{\frac{4}{3}} - \frac{2 x ^{\frac{3}{2}}}{3} + x^{2} - 4 x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{\frac{4}{3}}) - \frac{d}{d x} (\frac{2 x ^{\frac{3}{2}}}{3}) + \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) + \frac{d}{d x} (1)

\frac{d}{d x} (4 x^{\frac{4}{3}}) = \frac{16 x ^{\frac{1}{3}}}{3}

\frac{d}{d x} (\frac{2 x ^{\frac{3}{2}}}{3}) = x^{\frac{1}{2}}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (1) = 0

= \frac{16 x ^{\frac{1}{3}}}{3} - x^{\frac{1}{2}} + 2 x - 4 + 0

Vereinfache

= 2 x + \frac{16 x ^{\frac{1}{3}}}{3} - x^{\frac{1}{2}} - 4

n = 0 \sum \infty 2 \cdot 0. 2^{n}

x \to 0 lim (\frac{5 ^{x + 1} - 5}{x})

\int arctan (d) x d x

\frac{d}{d θ} (\frac{2}{1 - sin ( θ )})

x \to 5 lim (x^{2} + 5 x + 8)