y^'=(-1)/(x^2)

Lösung

y^{^{'}} = \frac{- 1}{x ^{2}}

y = \frac{1}{x} + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{- 1}{x ^{2}}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int \frac{- 1}{x ^{2}} d x

\int \frac{- 1}{x ^{2}} d x = \frac{1}{x} + c_{1}

y = \frac{1}{x} + c_{1}

n = 0 \sum \infty \frac{1}{5} \cdot (- \frac{2}{3})^{n}

t an g e n t x^{2} + y^{2} = 25, (- 4, 3)

x \to 0 + lim (cos (\frac{π}{x}))

\frac{d}{d x} ((1 + x)^{\frac{1}{3}})

x \to x lim (\frac{x ^{2} - 1}{x - 1})