f^'(x)=e^{-2x}

Lösung

f^{^{'}} (x) = e^{- 2 x}

f (x) = - \frac{1}{2} e^{- 2 x} + c_{1}

Schritte zur Lösung

f^{'} (x) = e^{- 2 x}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

f (x) = \int e^{- 2 x} d x

\int e^{- 2 x} d x = - \frac{1}{2} e^{- 2 x} + c_{1}

f (x) = - \frac{1}{2} e^{- 2 x} + c_{1}

\frac{d}{d x} (\frac{2 x + sin ( x )}{2 x + cos ( x )})

s l o p e (1, 10), (24, - 26)

x \to 4 - lim (5 - x)

\frac{\partial}{\partial x} (\frac{1}{i} + \frac{1}{o})

\int_{0}^{2} (2 - x) d x