(dy)/(dx)=(y-1-2y+y+1)/(x^2)

Lösung

\frac{d y}{d x} = \frac{y - 1 - 2 y + y + 1}{x ^{2}}

y = c_{1}

Schritte zur Lösung

\frac{d y}{d x} = \frac{y - 1 - 2 y + y + 1}{x ^{2}}

Ersetze

\frac{d y}{d x}

mit

y^{'} (x)

y^{^{'}} (x) = \frac{y - 1 - 2 y + y + 1}{x ^{2}}

Vereinfache

y^{^{'}} (x) = 0

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 0 d x

\int 0 d x = c_{1}

y = c_{1}

a re a y = \frac{- x ^{3}}{2} - \frac{x ^{2}}{2} + \frac{5 x}{2}, y = \frac{- x}{2}

\int (- 2 e^{3 x} + \frac{5}{x}) d x

x \to + 1 lim (ln (x))

\int \frac{4 x ^{3} - 5 x ^{2}}{( x - 2 ) ( x + 1 )} d x

a re a 6 x, \frac{2}{3} x, 40 - x^{2}