taylor 25x^3-6x^2+7x-88

Lösung

taylor

25 x^{3} - 6 x^{2} + 7 x - 88

- 88 + 7 x - 6 x^{2} + 25 x^{3}

Schritte zur Lösung

Apply the Taylor Formula

= - 88 + \frac{\frac{d}{d x} ( 25 x ^{3} - 6 x ^{2} + 7 x - 88 ) ( 0 )}{1 !} x + \frac{\frac{d ^{2}}{d x ^{2}} ( 25 x ^{3} - 6 x ^{2} + 7 x - 88 ) ( 0 )}{2 !} x^{2} + \frac{\frac{d ^{3}}{d x ^{3}} ( 25 x ^{3} - 6 x ^{2} + 7 x - 88 ) ( 0 )}{3 !} x^{3} + \dots

Evaluate Derivatives

= - 88 + \frac{7}{1 !} x + \frac{- 12}{2 !} x^{2} + \frac{150}{3 !} x^{3} + \frac{0}{4 !} x^{4} + \frac{0}{5 !} x^{5} + \frac{0}{6 !} x^{6} + \frac{0}{7 !} x^{7} + \frac{0}{8 !} x^{8} + \frac{0}{9 !} x^{9} + \frac{0}{10 !} x^{10}

Fasse zusammen

= - 88 + 7 x - 6 x^{2} + 25 x^{3}

\int \frac{8 x ^{2}}{( 64 + x ^{2} ) ^{2}} d x

s l o p e (2.6) (4.12)

\int_{1}^{e^{6}} \frac{ln ^{2} ( x ^{2} )}{x} d x

a re a x = 25 - y - 5, x = y - 10

\frac{d}{d x} ((x^{2} - 4)^{2})