(4+x)(dy)/(dx)=y^3

Lösung

(4 + x) \frac{d y}{d x} = y^{3}

y = - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}, y = - - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}

Schritte zur Lösung

(4 + x) \frac{d y}{d x} = y^{3}

Solve separable ODE:

y = - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}, y = - - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}

y = - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}, y = - - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}

t an g e n t y = 2 x^{3} + 3 x^{2} - 12 x + 9

n = 1 \sum \infty \frac{( - 1 ) ^{n}}{2}

\frac{d}{d x} (ln (x) (x^{2} - 5))

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\frac{d}{d x} (1 - x^{2} arccos (x))