integral of x^2cos(1/9 x)

Lösung

\int x^{2} cos (\frac{1}{9} x) d x

9 x^{2} sin (\frac{1}{9} x) - 18 (- 9 x cos (\frac{1}{9} x) + 81 sin (\frac{1}{9} x)) + C

Schritte zur Lösung

\int x^{2} cos (\frac{1}{9} x) d x

Wende die partielle Integration an

= 9 x^{2} sin (\frac{1}{9} x) - \int 18 x sin (\frac{1}{9} x) d x

\int 18 x sin (\frac{1}{9} x) d x = 18 (- 9 x cos (\frac{1}{9} x) + 81 sin (\frac{1}{9} x))

= 9 x^{2} sin (\frac{1}{9} x) - 18 (- 9 x cos (\frac{1}{9} x) + 81 sin (\frac{1}{9} x))

Füge eine Konstante zur Lösung hinzu

= 9 x^{2} sin (\frac{1}{9} x) - 18 (- 9 x cos (\frac{1}{9} x) + 81 sin (\frac{1}{9} x)) + C

\frac{d}{d x} (sec (x) tan^{2} (x))

\frac{\partial}{\partial x} (\frac{x ^{2} - y}{x ^{2} + y})

\int \frac{8 cosh ( x )}{x} d x

\int \frac{( 5 - x )}{2 x ^{2} + x - 1} d x

z \to 2 lim (\frac{z ^{2} + 3}{i z})