What is the tangent of cos(5+x^2) ?

The tangent of cos(5+x^2) is y=-sin(5+a_{0}^2)*2a_{0}x+cos(5+a_{0}^2)+2a_{0}^2sin(5+a_{0}^2)

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tangent of cos(5+x^2)

tangent of

cos (5 + x^{2})

y = - sin (5 + a_{0}^{2}) \cdot 2 a_{0} x + cos (5 + a_{0}^{2}) + 2 a_{0}^{2} sin (5 + a_{0}^{2})

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, cos (5 + a_{0}^{2}))

Find the slope of

y = cos (5 + x^{2}) : \frac{d y}{d x} = - sin (5 + x^{2}) \cdot 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - sin (5 + a_{0}^{2}) \cdot 2 a_{0}

Find the line with slope m=

- sin (5 + a_{0}^{2}) 2 a_{0}

and passing through

(a_{0}, cos (5 + a_{0}^{2})) : y = - sin (5 + a_{0}^{2}) \cdot 2 a_{0} x + cos (5 + a_{0}^{2}) + 2 a_{0}^{2} sin (5 + a_{0}^{2})

y = - sin (5 + a_{0}^{2}) \cdot 2 a_{0} x + cos (5 + a_{0}^{2}) + 2 a_{0}^{2} sin (5 + a_{0}^{2})

What is the tangent of cos(5+x^2) ?
The tangent of cos(5+x^2) is y=-sin(5+a_{0}^2)*2a_{0}x+cos(5+a_{0}^2)+2a_{0}^2sin(5+a_{0}^2)