What is the tangent of f(x)=x^2-3x,\at x=2 ?

The tangent of f(x)=x^2-3x,\at x=2 is y=x-4

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tangent of f(x)=x^2-3x,\at x=2

tangent of

f (x) = x^{2} - 3 x, at x = 2

y = x - 4

Solution steps

Find the tangent point:

(2, - 2)

Find the slope of

f (x) = x^{2} - 3 x : \frac{df ( x )}{d x} = 2 x - 3

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 1

Find the line with slope m=

1

and passing through

(2, - 2) : y = x - 4

y = x - 4

What is the tangent of f(x)=x^2-3x,\at x=2 ?
The tangent of f(x)=x^2-3x,\at x=2 is y=x-4