derivative f(x)=x^2-4x-5

解

導関数

f (x) = x^{2} - 4 x - 5

2 x - 4

解答ステップ

\frac{d}{d x} (x^{2} - 4 x - 5)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) - \frac{d}{d x} (4 x) - \frac{d}{d x} (5)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (5) = 0

= 2 x - 4 - 0

簡素化

= 2 x - 4