What is the tangent of f(x)=(x-2)^{1/2},\at x=6 ?

The tangent of f(x)=(x-2)^{1/2},\at x=6 is y= 1/4 x+1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

tangent of f(x)=(x-2)^{1/2},\at x=6

tangent of

f (x) = (x - 2)^{\frac{1}{2}}, at x = 6

y = \frac{1}{4} x + \frac{1}{2}

Solution steps

Find the tangent point:

(6, 2)

Find the slope of

f (x) = (x - 2)^{\frac{1}{2}} : \frac{df ( x )}{d x} = \frac{1}{2 ( x - 2 ) ^{\frac{1}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = \frac{1}{4}

Find the line with slope m=

\frac{1}{4}

and passing through

(6, 2) : y = \frac{1}{4} x + \frac{1}{2}

y = \frac{1}{4} x + \frac{1}{2}

What is the tangent of f(x)=(x-2)^{1/2},\at x=6 ?
The tangent of f(x)=(x-2)^{1/2},\at x=6 is y= 1/4 x+1/2