What is the tangent of y= 1/(x^2),(-1,1) ?

The tangent of y= 1/(x^2),(-1,1) is y=2x+3

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tangent of y= 1/(x^2),(-1,1)

tangent of

y = \frac{1}{x ^{2}}, (- 1, 1)

y = 2 x + 3

Solution steps

Find the slope of

y = \frac{1}{x ^{2}} : \frac{d y}{d x} = - \frac{2}{x ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 2

Find the line with slope m=

2

and passing through

(- 1, 1) : y = 2 x + 3

y = 2 x + 3

What is the tangent of y= 1/(x^2),(-1,1) ?
The tangent of y= 1/(x^2),(-1,1) is y=2x+3