What is area 1/(x+1),((x-1))/2 ?

The answer to area 1/(x+1),((x-1))/2 is ln(2)+1/4

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area 1/(x+1),((x-1))/2

area

\frac{1}{x + 1}, \frac{( x - 1 )}{2}

ln (2) + \frac{1}{4}

Decimal

0.94314 \dots

Solution steps

Apply the area formula:

\int_{0}^{1} \frac{1}{x + 1} - \frac{1}{2} (x - 1) d x

Solve

\int_{0}^{1} \frac{1}{x + 1} - \frac{1}{2} (x - 1) d x : ln (2) + \frac{1}{4}

The area is:

= ln (2) + \frac{1}{4}

What is area 1/(x+1),((x-1))/2 ?
The answer to area 1/(x+1),((x-1))/2 is ln(2)+1/4