(dy)/(dx)=(8e^{4x})/(2cos(2y))

Lösung

\frac{d y}{d x} = \frac{8 e ^{4 x}}{2 cos ( 2 y )}

y = \frac{arcsin ( 2 e ^{4 x} + c _{1} )}{2} + πn, y = \frac{π}{2} + \frac{arcsin ( - 2 e ^{4 x} - c _{1} )}{2} + πn

Schritte zur Lösung

\frac{d y}{d x} = \frac{8 e ^{4 x}}{2 cos ( 2 y )}

Solve separable ODE:

y = \frac{arcsin ( 2 e ^{4 x} + c _{1} )}{2} + πn, y = \frac{π}{2} + \frac{arcsin ( - 2 e ^{4 x} - c _{1} )}{2} + πn

y = \frac{arcsin ( 2 e ^{4 x} + c _{1} )}{2} + πn, y = \frac{π}{2} + \frac{arcsin ( - 2 e ^{4 x} - c _{1} )}{2} + πn

t a y l or \frac{1}{3 x + 5}

\frac{\partial}{\partial y} (x - \frac{1}{y ^{2}})

in v erse l a pl a ce \frac{1}{( s ^{2} + s + 1 )}

x \to 5 lim (4 x - 3)

d er i v a t i v e \frac{6}{4 x + 1}