What is the integral of (ln(x))/(16) ?

The integral of (ln(x))/(16) is 1/16 (xln(x)-x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (ln(x))/(16)

\int \frac{ln ( x )}{16} d x

\frac{1}{16} (x ln (x) - x) + C

Solution steps

\int \frac{ln ( x )}{16} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{16} \cdot \int ln (x) d x

Apply Integration By Parts

= \frac{1}{16} (x ln (x) - \int 1 d x)

\int 1 d x = x

= \frac{1}{16} (x ln (x) - x)

Add a constant to the solution

= \frac{1}{16} (x ln (x) - x) + C

What is the integral of (ln(x))/(16) ?
The integral of (ln(x))/(16) is 1/16 (xln(x)-x)+C