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Popular Calculus >

xe^xy^'+2e^xy=0

Solution

x e^{x} y^{^{'}} + 2 e^{x} y = 0

Solution

y = \frac{c _{1}}{x ^{2}}

Solution steps

x e^{x} y^{'} (x) + 2 e^{x} y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{2}}

y = \frac{c _{1}}{x ^{2}}

Graph

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\frac{\partial}{\partial x} ((x^{2} + 9 x - 4 y)^{6})

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\frac{d}{d x} (\frac{2 x - 1}{x})

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\int - csc (x) cot (x) d x

Frequently Asked Questions (FAQ)

What is the solution for xe^xy^'+2e^xy=0 ?
The solution for xe^xy^'+2e^xy=0 is y=(c_{1})/(x^2)