What is (\partial)/(\partial x)(sin(2x)cos(y)) ?

The answer to (\partial)/(\partial x)(sin(2x)cos(y)) is cos(y)cos(2x)*2

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(\partial)/(\partial x)(sin(2x)cos(y))

\frac{\partial}{\partial x} (sin (2 x) cos (y))

cos (y) cos (2 x) \cdot 2

Solution steps

\frac{\partial}{\partial x} (sin (2 x) cos (y))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= cos (y) \frac{\partial}{\partial x} (sin (2 x))

Apply the chain rule:

cos (2 x) \frac{\partial}{\partial x} (2 x)

= cos (2 x) \frac{\partial}{\partial x} (2 x)

\frac{\partial}{\partial x} (2 x) = 2

= cos (y) cos (2 x) \cdot 2

What is (\partial)/(\partial x)(sin(2x)cos(y)) ?
The answer to (\partial)/(\partial x)(sin(2x)cos(y)) is cos(y)cos(2x)*2