(3x^2y^2+y)dx+(2x^3y+x)dy=0

Lösung

(3 x^{2} y^{2} + y) d x + (2 x^{3} y + x) d y = 0

y = \frac{- 1 + 4 c _{1} x + 1}{2 x ^{2}}, y = - \frac{4 c _{1} x + 1 + 1}{2 x ^{2}}

Schritte zur Lösung

(3 x^{2} y^{2} + y) d x + (2 x^{3} y + x) d y = 0

Solve exact ODE:

y = \frac{- 1 + 4 c _{1} x + 1}{2 x ^{2}}, y = - \frac{4 c _{1} x + 1 + 1}{2 x ^{2}}

y = \frac{- 1 + 4 c _{1} x + 1}{2 x ^{2}}, y = - \frac{4 c _{1} x + 1 + 1}{2 x ^{2}}

\int_{0}^{\frac{π}{6}} cos^{3} (x) d x

\int 16 x ln (7 x) d x

\int_{0}^{\frac{π}{2}} 11 sin^{2} (2 x) d x

\frac{d}{d x} (x^{3} \cdot sin^{2} (5 x))

\frac{\partial}{\partial x} (\frac{sin ( x )}{sin ( y )})