y^'t^4=0

Lösung

y^{^{'}} t^{4} = 0

y = c_{1}

Schritte zur Lösung

y^{'} (t) t^{4} = 0

Isoliere

y^{'} (t) : y^{'} (t) = 0

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int 0 d t

\int 0 d t = c_{1}

y = c_{1}

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