laplacetransform 3sin(4t)

Lösung

laplace transformation

3 sin (4 t)

\frac{12}{s ^{2} + 16}

Schritte zur Lösung

L {3 sin (4 t)}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= 3 L {sin (4 t)}

L {sin (4 t)} : \frac{4}{s ^{2} + 16}

= 3 \cdot \frac{4}{s ^{2} + 16}

Fasse

3 \frac{4}{s ^{2} + 16}

zusammen:

\frac{12}{s ^{2} + 16}

= \frac{12}{s ^{2} + 16}

\frac{d}{d x} (cos (x^{l n (x^{2} + 1)}))

x \to 0 lim (\frac{x - x}{x})

8 x^{^{''}} + 8 x^{^{'}} + \frac{1}{4} x = 0, x^{^{'}} (0) = 1, x (0) = 2

\int u^{\frac{3}{2}} d u

\int x cos^{2} (x) d x