derivative of 900x-1/3 x^3+2500

Lösung

\frac{d}{d x} (900 x - \frac{1}{3} x^{3} + 2500)

- x^{2} + 900

Schritte zur Lösung

\frac{d}{d x} (900 x - \frac{1}{3} x^{3} + 2500)

Vereinfache

900 x - \frac{1}{3} x^{3} + 2500 : 900 x - \frac{x ^{3}}{3} + 2500

= \frac{d}{d x} (900 x - \frac{x ^{3}}{3} + 2500)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (900 x) - \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (2500)

\frac{d}{d x} (900 x) = 900

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (2500) = 0

= 900 - x^{2} + 0

Vereinfache

= - x^{2} + 900

\int \frac{- x + 1}{x ^{2} + x + 1} d x

5 y^{^{''}} + 5 y^{^{'}} - 10 y = 0

\int_{- \infty}^{0} (4 - 3 x) e^{x} d x

\int_{0}^{4} \frac{3}{x ^{2}} d x

\frac{d ^{2}}{d x ^{2}} (5 e^{x})