What is the integral of 1/((x-2)^2) ?

The integral of 1/((x-2)^2) is -1/(x-2)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/((x-2)^2)

\int \frac{1}{( x - 2 ) ^{2}} d x

- \frac{1}{x - 2} + C

Solution steps

\int \frac{1}{( x - 2 ) ^{2}} d x

Apply u-substitution

= \int \frac{1}{u ^{2}} d u

Apply the Power Rule

= - \frac{1}{u}

Substitute back

u = x - 2

= - \frac{1}{x - 2}

Add a constant to the solution

= - \frac{1}{x - 2} + C