derivative of (9x^2-3x-10y^{''}+(x^2+x)y^'+(2x-1)y)

Lösung

\frac{d}{d x} ((9 x^{2} - 3 x - 10) y^{^{''}} + (x^{2} + x) y^{^{'}} + (2 x - 1) y)

Schritte zur Lösung

\frac{d}{d x} ((9 x^{2} - 3 x - 10) y^{^{''}} + (x^{2} + x) y^{^{'}} + (2 x - 1) y)

Vereinfache

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

\frac{d}{d x} ((x^{2} + x) y^{^{'}}) = (2 x + 1) y^{^{'}} +^{'} \frac{d y}{d x} y^{^{'} - 1} (x^{2} + x)

\frac{d}{d x} ((2 x - 1) y) = 2 y + \frac{d y}{d x} (2 x - 1)

\frac{\partial}{\partial x} (tan (6 + 2 x^{2} y^{3} z^{2}))

\frac{d y}{d x} = \frac{x - y}{x}

\frac{\partial}{\partial x} (x^{2} - y^{2} + 5 x y)

m = 1 \sum \infty 3 \cdot (\frac{1}{3})

\int (x - 3)^{2} sin (x - 3) d x