What is the (sqrt(4-x^2))^' ?

The (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))

What is the first (sqrt(4-x^2))^' ?

The first (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))

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(4 - x^{2})^{^{'}}

- \frac{x}{4 - x ^{2}}

Solution steps

(4 - x^{2})^{'}

Apply the chain rule:

\frac{1}{2 4 - x ^{2}} (4 - x^{2})^{'}

= \frac{1}{2 4 - x ^{2}} (4 - x^{2})^{'}

(4 - x^{2})^{'} = - 2 x

= \frac{1}{2 4 - x ^{2}} (- 2 x)

Simplify

\frac{1}{2 4 - x ^{2}} (- 2 x) : - \frac{x}{4 - x ^{2}}

= - \frac{x}{4 - x ^{2}}

What is the (sqrt(4-x^2))^' ?
The (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))
What is the first (sqrt(4-x^2))^' ?
The first (sqrt(4-x^2))^' is -x/(sqrt(4-x^2))