limit as x approaches 1 of ln(7x)+e^x

解答

x \to 1 lim (ln (7 x) + e^{x})

ln (7) + e

十进制

4.66419 \dots

求解步骤

x \to 1 lim (ln (7 x) + e^{x})

代入值

x = 1

= ln (7 \cdot 1) + e^{1}

化简

= ln (7) + e

\int \frac{5 x - 2}{x ^{2} - 4} d x

y^{^{'}} = x y^{2} + 2 y^{2}, y (0) = 1

d er i v a t i v e f (x) = \frac{2 x ^{2} - 6 x + 5}{2 ( 2 x - 3 )}

\frac{d y}{d x} = sec^{2} (x) (2 + y)^{2}

in v erse l a pl a ce \frac{s + 6}{s ^{2} + 6 s + 25}